**Problem of the week**

One
goes on spiraling walk on cartesian
plane. Starting at (0,0).

The
first five steps are (1,0) (1,1) (0,1), (-1, 1) and
(-1,0).

Find the point on 2002^{nd} step.

Send your solution by 19 Aug 2017 on
pow@madanpur.in

Correct solution received from:

1.

2.

3.