14 November 2016

**Question:** *There
is an escalator and 2 persons are climbing down on it.*

* A climbs down 50 steps and B climbs down 75
steps*

* while the escalator
is moving down.*

* Given that the time taken by A to take 1 step
is equal *

*to** the time taken by B to take 3 steps, *

*find** the total number of steps in the escalator while it is
stationary.*

**Solution:**

Let A take 1 step/min. Hence,
B takes 3 steps/min.

Let the
escalator take n steps/min. Given that A takes 50 steps and hence in the same
time, the escalator will take 50n steps. Because A is moving 50 steps,

it means that the
time taken is 50 minutes. Therefore, the total no. of steps must be 50 + 50n.

It is given that B takes 75 steps (which means that he takes 25 min). So, in the same time,

the escalator
will cover 25n steps. Therefore, the no. of steps must be 75 + 25n.

Equating 50
+ 50n = 75 + 25n, we get n = 1. Therefore, the total number of steps = **100**.

**Correct solution received from
:**

**1.**

**2.**

**3.**

**4.**

**5.**