Q.5. **A
square sheet of paper ABCD is so folded that B falls on the midpoint M of CD. Prove
that the crease will divide BC in the ratio 5:3.**

Solution: 1^{st}

Let ABCD be a square with side ‘a’ units.

Let PQ be the crease formed when the paper ABCD is folded on the midpoint M of
CD.

Let QC = x

When the paper will be folded along the crease of course B will coincide with
M.

∴
BQ = QM = a – x

Also since M is the mid point of BC. Then MC=a/2

Therefore, we get BQ:QC=5:3

That is crease will divide BC in the
ratio 5 : 3.