Q.5. A square sheet of paper ABCD is so folded that B falls on the midpoint M of CD. Prove that the crease will divide BC in the ratio 5:3.

Solution: 1st

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Let ABCD be a square with side a units.
Let PQ be the crease formed when the paper ABCD is folded on the midpoint M of CD.
Let QC = x
When the paper will be folded along the crease of course B will coincide with M.
BQ = QM = a x

Also since M is the mid point of BC. Then MC=a/2

 

Therefore, we get BQ:QC=5:3

That is crease will divide BC in the ratio 5 : 3.

ALITER

 

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